Prepared by IQInsight · Calculation guide · Updated
121 sits just inside the band many manuals call superior.
A score of 121 is 1.4 standard deviations above the mean. The normal model places about 91.92% of values below it and 8.08% at or above it, around one in twelve. On WAIS-IV classifications, 120 to 129 is labelled superior; newer manuals such as the WISC-V call the same band very high.
Compared with 120, which is higher than about 90.88% of values, 121 is roughly one percentile point higher. Top 10% is a fair rounded description of both. The label changes at 120 only because a boundary has to be drawn somewhere.
How test manuals label 121.
Professional tests describe score ranges with standard labels. On the WAIS-IV, 121 falls in the superior range; the newer WISC-V calls the same range very high. The labels describe ranges on those specific tests and change at fixed boundaries, so a score a point or two from an edge is not meaningfully different from one just across it.
| Score range | WAIS-IV label | WISC-V label |
|---|---|---|
| 130 and above | Very superior | Extremely high |
| 120–129 (121) | Superior | Very high |
| 110–119 | High average | High average |
| 90–109 | Average | Average |
| 80–89 | Low average | Low average |
| 70–79 | Borderline | Very low |
| 69 and below | Extremely low | Extremely low |
High-IQ societies such as Mensa admit people who score at or above the 98th percentile on an approved, supervised test, roughly 130 on an SD-15 scale. Online estimates, including IQInsight’s, do not count toward membership.
How precise is one result?
Every test score contains some measurement error. Professionally normed tests report a confidence interval, a band of several points around the score, and two results a few points apart often overlap. IQInsight has not been calibrated against a representative population, so it cannot provide a reliable interval for its estimates.
How the percentile is calculated.
The reference uses a mean of 100 and a standard deviation of 15. First convert the score to a z-score, then find the area below it on the standard normal curve.
z = (121 − 100) ÷ 15 = 1.4000
Percentile = Φ(z) × 100 ≈ 91.92%
At or above = (1 − Φ(z)) × 100 ≈ 8.08%
Approximate rarity = 1 ÷ (1 − Φ(z)) ≈ 1 in 12
Calculations use full precision before rounding. Φ is the cumulative standard normal distribution; the NIST statistical handbook explains this mathematical function. This reference does not validate IQInsight or any individual test.